2x2+6x^2-108x=0

Solution for 2x2+6x^2-108x=0 equation:

2x^2+6x^2-108x=0

We add all the numbers together, and all the variables

8x^2-108x=0

a = 8; b = -108; c = 0;
Δ = b2-4ac
Δ = -1082-4·8·0
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11664}=108$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-108)-108}{2*8}=\frac{0}{16}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-108)+108}{2*8}=\frac{216}{16}
=13+1/2
$